一道超简单的物理题啊..再次帮帮忙啊

2025-12-18 00:10:17
推荐回答(1个)
回答1:

保温时工作电流约是30W÷220V=0.136A
煮水6min,消耗的电能为700W×6min=0.7KW×0.1H=0.07KWH