初二代数,有点难度

2025-12-15 21:25:17
推荐回答(2个)
回答1:

=(x²+3x+9)/(x-2)(x-2) * 3(x-2)/(x-3)(x²+3x+9) *(x-3)(x+3)
=3(x+3)/(x-2)

回答2:

x²+3x+9/x²-4x+4 × 3x-6/x³-27 × (x²-9)
=x²+3x+9/(x-2)²×3(x-2)/(x-3)(x²+3x+9) × (x-3)(x+3)
=3(x+3)/(x-2)