以知函数f(x)=cos4次方x-2sincosx-sin4次方x.求F(X)最小正周期

2025-12-17 01:34:27
推荐回答(1个)
回答1:

f(x) = (cosx)^4 - 2sixcosx - (sinx)^4= (cos?x + sin?x)(cos?x - sin?x) - sin2x= cos2x - sin2x= √2cos(2x + π/4) 【sin(π/4) = cos(π/4) = √2/2】最小正周期为T = 2π/2 = π